Home

Physics

Cosmology

Units for astronomical distances

Units for astronomical distances

Select Lesson

Exam Board

AQA

AQAOCR APearson Edexcel

Explainer Video

Tutor: Kirsty

Summary

Units for astronomical distances

​​In a nutshell

Astronomical distances are so large that measuring them in metres is unhelpful. Instead, specialist units are used which are the astronomical  unit, light-year and parsec. Stellar parallax is used to calculate the distance from the Earth to a relatively near star. 


Equations

DESCRIPTION 

EQUATION

Distance to a star in parsecs
d=1pd = \dfrac{1}{p}​​


Constants

CONSTANT

SYMBOL

VALUE

1 astronomical unit1 \space astronomical \space unit​​
dd​​
1.50×1011 m1.50 × 10^{11} \,m​​
1 lightyear1 \space light-year​​
dd​​
9.46×1015 m9.46 × 10^{15} \, m
1 parsec1 \space parsec​​
dd​​
2.06×105 AU3.08×1016 m3.26 ly2.06 × 10^{5} \,AU \newline 3.08 × 10^{16} \,m \\[0.025in] \newline 3.26\, ly​​


The astronomical unit (AU)

The astronomical unit​ is the distance between the Earth and the sun, which is 1.50×1011m1.50 × 10^{11} m. It is mainly used to measure distances between planets and the Sun.​


Physics; Cosmology; KS5 Year 12; Units for astronomical distances


The light-year (ly)

The light-year​ is the distance travelled by light in a vacuum in one year, which is 9.46×1015 m9.46 × 10^{15} \,m. This is calculated by:


 distance=speed×timedistance=3×108ms1×365×24×60×601 lightyear=9.46×1015 mdistance = speed \times time \newline \\[0.1in] distance = 3 × 10^8ms^{-1} × 365 × 24 × 60 × 60 \newline \\[0.1in]1 \space light-year = 9.46 × 10^{15} \, m


Example 

A meteor is approximately 5.35 lightyears5.35 \ light-years​ from Earth. Calculate the distance between the Earth and the meteor in astronomical units.


State variables:

1 lightyear=9.5×1015 m1\ light-year = 9.5 × 10^{15} \, m

1 AU=1.496×1011 m1 \ AU = 1.496 × 10^{11}\, m​​

Distance to the meteorite = 5.35 ly5.35 \,ly

​​

Convert into metres​:

5.35 ly=5.35×(9.5×1015)5.35 ly=4.82×1016 m5.35 \, ly = 5.35 × (9.5 × 10^{15}) \newline 5.35 \, ly = 4.82 × 10^{16} \, m

​​

Convert from metres to AU​:


4.82×10161.496×1011=3.2×105AU\dfrac{4.82 \times 10^{16}}{1.496 \times 10^{11}} = 3.2 × 10^{5} AU  (to 2sf)


The meteor is 3.2×105AU \underline{ 3.2 × 10^{5} AU } from the Earth.


The parsec (pc)

The parsec is the distance that a radius of AU​ subtends an angle of 1 arcsecond1 \,arcsecond. Angles in astronomy are measured in arcminutesarcminutes​ and arcsecondsarcseconds​ instead of degrees, there are 60 arcminutes60 \, arcminutes in 1°1\degree and 60 arcseconds60 \, arcseconds in an arcminute:


 1 arcminute=(160)°1 arcsecond=(13600)°1 \space arcminute = (\dfrac{1}{60})^\degree \newline \\[0.05in]1 \space arcsecond = (\dfrac{1}{3600})^\degree


Physics; Cosmology; KS5 Year 12; Units for astronomical distances



Using the triangle above, the value of a parsec​ can be calculated as below:


tan(arcsecond)=1AU1pc1pc=1.50×1011tan(13600)1pc=3.1×1016 mtan(arcsecond) = \dfrac{1 AU}{1 pc} \newline \\[0.1in]1 pc =\dfrac{1.50 \times 10^{11}}{tan(\dfrac{1}{3600})} \newline \\[0.1in]1 pc= 3.1 \times 10^{16}\,m


Example 

A meteor is approximately 5.35 lightyears5.35 \ light-years​ from Earth. Calculate the distance between the Earth and the meteor in parsecs.


State variables:


1 parsec3.1×1016 m1 \ parsec ≈ 3.1 × 10^{16} \,m​​

5.35 ly=5.35×(9.5×1015)5.35 ly=4.82×1016 m5.35 \, ly = 5.35 × (9.5 × 10^{15}) \newline 5.35 \, ly = 4.82 × 10^{16} \, m


Convert from metres into parsecs​:


 4.82×1016 m3.1×1016=1.3 pc \dfrac{4.82 \times 10^{16} \, m}{3.1 \times 10^{16}} = 1.3 \,pc



The meteor is 1.3 parsecs \underline{ 1.3 \ parsecs} from the Earth.

Stellar parallax

Stellar parallax is a tool used to calculate the distance between the sun and a nearby star, and is the apparent shift of a star against more distant stars. 


You can see the effect of parallax yourself if you put your thumb in front of you, and close one eye at a time. Your thumb will appear to move, but the background will not! 


Physics; Cosmology; KS5 Year 12; Units for astronomical distances
Physics; Cosmology; KS5 Year 12; Units for astronomical distances


The parallax angle, which can be used to calculate the distance, is calculated by measuring the apparent distance to a star from the Earth at a specific time period, and using precise measurements to determine the parallax angle. The distance to a star in parsecs can then be calculated by:


d=1pd = \dfrac{1}{p}


where dd is the distance to the star in parsecs​ and pp is the parallax angle.


Example

A star close to the Earth, 61 Cygni has a parallax angle of 0.29 arcseconds0.29 \ arcseconds, calculate the distance from Earth to 61 Cygni in parsecs​.


State variables:

p=0.29 arcsecondsp = 0.29 \ arcseconds


State equation:

d=1pd = \dfrac{1}{p}


Substitute values in and solve:


d=10.29d=3.5 pcd = \dfrac{1}{0.29} \newline \\[0.1in]d = 3.5 \ pc


The star 61 Cygni is 3.5 pc\underline{3.5 \ pc} from the Earth. 



Read more

Learn with Basics

Length:
Units and equations

Units and equations

Physical quantities and units

Physical quantities and units

Jump Ahead

Units for astronomical distances

Units for astronomical distances

Final Test

Create an account to complete the exercises

FAQs - Frequently Asked Questions

What is stellar parallax?

What is a parsec?

What is a light-year?