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Potential difference and electromotive force

Potential difference and electromotive force

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Summary

Potential difference and electromotive force

In a nutshell

Potential difference is defined as the energy transferred per unit charge between two points in a circuit. The electromotive force is the energy per unit charge given to the charge carriers by a power source. Voltmeters have to be placed in parallel to measure the potential difference between two points.


Equations

Description

Equation

Potential difference
V=WQV=\dfrac{W}{Q}​​
Electromotive force
ε=WQ\varepsilon =\dfrac{W}{Q}​​

Variable definitions

Quantity name

symbol

derived units

alternate units

si base units

potential differencepotential\ difference​​
VV​​
VV​​
J C1J\ C^{-1}​​
kg m2 s3 A1kg\ m^2\ s^{-3}\ A^{-1}​​
work donework\ done​​
WW​​
JJ​​
eVeV​​
kg m2 s2kg\ m^{2}\ s^{-2}​​
chargecharge​​
QQ​​
CC​​

A sA\ s​​
electromotive forceelectromotive\ force​​
ε\varepsilon​​
VV​​
J C1J\ C^{-1}​​
kg m2 s3 A1kg\ m^2\ s^{-3}\ A^{-1}​​


Potential difference

Potential difference or voltage is a measure of how much energy is transferred by charge carriers to a circuit component. It is defined as the energy transferred per unit charge between two points in a circuit. It is symbolised by the letter VV and is measured in volts VV. You can calculate it with the equation:


V=WQV=\dfrac{W}{Q}​​


Electromotive force

Potential difference describes the work done by the charge carriers i.e. the energy given to the components by the charge carriers. The electromotive force (e.m.f.) on the other hand, is the work done on the charge carriers or the energy given to the charge carriers by a power source. It is symbolised by the greek letter ε\varepsilon and is measured in volts VV. You can calculate it with the equation:


ε=WQ\varepsilon=\dfrac{W}{Q}​​

Using a voltmeter

A voltmeter is a component that is used to measure the potential difference between two points in a circuit by placing it in parallel to a component. You can also use it to measure the e.m.f. of a power supply by placing it in parallel to one. A voltmeter has a very high resistance in order to minimise the current flowing through it since current splits in parallel circuits.  


Physics; Electrical circuits; KS5 Year 12; Potential difference and electromotive force


Example

In the circuit above the cell provides 20 C20\ C of charge carriers with 200 J200\ J of energy. 40 J40\ J are then transferred to the resistor, calculate the e.m.f of the cell and the potential difference across the resistor.


Firstly, write down what you know:


Q=20 CWcell=200 JWresistor=40 J\begin{aligned}Q&=20\ C \\W_{cell}&= 200\ J \\W_{resistor} &=40\ J\end{aligned}​​


Next, write down the equation for the e.m.f.:


ε=WQ\varepsilon=\dfrac{W}{Q}​​


In this case you have to use the work done by the cell:


ε=WcellQ\varepsilon=\dfrac{W_{cell}}{Q}​​


Substitute the numbers in and calculate the e.m.f:


ε=20020=10 V\varepsilon=\dfrac{200}{20}=10\ V​​


Now write down the equation for voltage:


V=WQV=\dfrac{W}{Q}​​


Since you are calculating the voltage across the resistor you have to use the work done on the resistor by the charge carriers:


V=WresistorQV=\dfrac{W_{resistor}}{Q}​​


Substitute the number and calculate the potential difference:


V=4020=2 VV=\dfrac{40}{20}=2\ V​​


The e.m.f. of the cell is 20 V\underline{20\ V} and the potential difference across the resistor is 2 V\underline{2\ V}​.

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Learn with Basics

Length:
Measuring current and potential difference

Unit 1

Measuring current and potential difference

Potential difference and resistance

Unit 2

Potential difference and resistance

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Potential difference and electromotive force

Unit 3

Potential difference and electromotive force

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FAQs - Frequently Asked Questions

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