Volume and pressure calculations
In a nutshell
When gas pressure is constant, volume is directly proportional to temperature. When temperature is constant, pressure is inversely proportional to volume.
Equations
Word Equation
| Symbol Equation |
pressure × volume=constant | |
pressure object 1×volume object 1=pressure object 2×volume object 2 | p1×V1=p2×V2 |
Variable definitions
Quantity Name
| Symbol
| Unit Name
| Unit |
pressure | | | |
| | cubic metre | |
constant | | Pascal cubic metre | |
Volume and pressure
Consider a container of gas with a movable wall:
Initially, the gas inside the container has the same pressure as the air outside, so the wall remains stationary.
Moving the wall inwards, decreases the volume available for the gas. This means the gas particles hit the walls of the container more often. Assuming that temperature remains constant, the pressure increases.
The formula relating the pressure and volume of a gas at a constant temperature is:
pressure×volume=constant p×V=C
where the variables are defined above.
The product of an object's pressure and volume at constant temperature is equal to a constant, C. This means for two different objects, the products of their pressure and volumes at the same temperature will equal the same constant.
This means that we can equate the two objects as they are equal to each other:
pressure object 1×volume object 1=pressure object 2×volume object 2 p1×V1=p2×V2
Note: Object 1 and Object 2 can either be the same object but in two different points in time or they could be two completely independent objects as long as the temperature remains constant.
Example
The volume of a gas in a sealed cylinder starts at 5.0×10−5m3 with a pressure of 1.2×106Pa. A piston is pushed slowly into the cylinder, increasing the gas pressure to 2.0×106Pa. What is the new volume of the gas assuming the temperature remains constant?
Write down the relevant information provided in the question (converting to base units where appropriate):
p1=1.2×106Pa V1=5.0×10−5m3 p2=2.0×106Pa.
Write down the relevant formula:
p×V=constant p1×V1=p2×V2.
Rearrange the formula:
V2=p2p1×V1.
Substitute the values into the correct formula:
V2=2.0×1061.2×106×5.0×10−5 V2=3.0×10−5m3.
So the new volume of the gas is 3.0×10−5m3.