Centre of mass
In a nutshell
Objects can be non-uniform, which means the centre of mass is not necessarily at the midpoint. Using forces and moments you can find the centre of mass.
Centre of mass
With a non-uniform rod, you may have to find the position of its centre of mass. The centre of mass can be found by considering the moment due to the weight of the rod. By taking moments about a point, you can create an equation to find the distance of the centre of mass from the point.
Example 1
A non-uniform rod AB is 4m long and has a weight of 25N. It rests in a horizontal equilibrium on supports C and D, where AC=1m and AD=3m. The magnitude of the reaction at C is four times the magnitude of the reaction at D. Find the distance of the centre of mass of the rod from A.
Find the magnitude of the reactions:
Take the reaction at D to be R, therefore the reaction at C is 4R. Resolve vertically:
4R+R5RR=25=25=5
Therefore, the reaction at C is 20N and the reaction at D is 5N. Take moments about point A, supposing the centre of mass of the rod acts a point xm from A:
25x25x25xxx=20(1)+5(3)=20+15=35=2535=1.4
Therefore, the centre of the mass of the rod is 1.4m from A.
Example 2
Two people are sitting on a seesaw which is modelled as a non-uniform plank AB with a mass of 15kg and a length of 4m. The plank rests on a pivot P at the midpoint of AB. The centre of mass of the plank is at a point C, where AC=1.5m Person F has a mass of 20kg and sits at point A. Person G has a mass of 35kg and is sitting on the other side of the plank. Where on the plank does G have to sit for the plank to be horizontal? (G can be moved from the end of the plank B towards the pivot).
Take moments about the pivot P. Take person G's distance from the midpoint to be xm:
(20g×2)+(15g×0.5)40g+7.5g47.51.36=35g×x=35xg=35x=x
Therefore for the plank to be horizontal, person G must be sitting 1.36m from the pivot.