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Summary

Sine and cosine rules

In a nutshell

The sine and cosine rules can be used to work out a missing side or angle in any triangle. Similarly, the trigonometric area of a triangle can be used to find the area of a triangle without being given the perpendicular height.

Labelling a triangle

It is common convention to label the vertices (and corresponding angle) of a triangle with capital letters. The side opposite the angle is labelled with its lowercase counterpart. Here is a diagram to illustrate:

Maths; Trigonometry; KS4 Year 10; Sine and cosine rules - Higher

The sine rule

When is it used?

The sine rule is used when you have an angle-side pair (e.g. side $B$ and angle $b$ ), and either another side or another angle.

The sine rule formula

There are two forms of the sine rule: the side form and the angle form.

Side form	Angle form
$\frac{a}{\sin(A)}=\frac{b}{\sin(B)}=\frac{c}{\sin(C)}$	$\frac{\sin(A)}{A}=\frac{\sin(B)}{b}=\frac{\sin(C)}{c}$

Example 1

In the diagram above, the angles $A$ and $B$ are $40^\circ$ and $70^\circ$ respectively. If the side $a$ is $5cm$ long, what is the length of side $b$ to the nearest integer?

You are given $A$ , $B$ , $a$ and you are told to find the value of $b$ . So, use the first 2 fractions of the sine rule. Use the side form as you need to find a length:

$\frac{a}{\sin(A)}=\frac{b}{\sin(B)}$

Substitute the known values:

$\frac{5}{\sin(40)}=\frac{b}{\sin(70)}$

Solve for $b$ :

b = \sin(70)\times \frac{5}{\sin(40)} = 7.309511...

$\underline{b =7cm}$ to the nearest integer.

The cosine rule

When is it used?

The cosine rule is used when you have three sides or two sides and the angle between them.

The cosine rule formula

Again, there are two forms of the cosine rule: the side form and the angle form.

Side form	Angle form
$a^2=b^2+c^2-2bc\cos(A)$	$\cos(A)=\frac{b^2+c^2-a^2}{2bc}$

Tip: If you're confident enough in your algebra and rearranging, you can just memorise the side form.

Example 2

The lengths of the sides of a triangle are $5cm$ , $7cm$ , and $10cm$ . What is the size of the angle opposite the side with length $7cm$ to 1 decimal place?

Always start off by drawing and labelling a sketch if you're not given one:

Note: Labelling correctly is very important when using the cosine rule. The angle form of the cosine rule has the angle $A$ , so make sure the side with length $7cm$ is labelled as $a$ . It doesn't matter which of the remaining sides you label $b$ and $c$ .

Now, use the angle form of the cosine rule:

$\cos(A)=\frac{b^2+c^2-a^2}{2bc}$

Substitute in known values:

$\cos(A)=\frac{10^2+5^2-7^2}{2(5)(10)}$

$\cos(A)=0.76$

Use the inverse cosine function to get the angle by itself:

$A=\cos^{-1}(0.76)=40.535802...$

$\underline{A=40.5\degree \ (1 \ d.p.)}$

Area of a triangle

When is it used?

This is used when you have two sides and the angle between them, and want to find the area of the triangle.

The formula for the area of a triangle

$Area=\frac{1}{2}ab\sin(C)$

Example 3

A triangle has sides $2cm$ , $4cm$ and the angle between them is $24^\circ$ . Find the area of the triangle to 2 decimal places.

Sketch the triangle first and label the sides and angles.

Note: Again, it's important to label your triangle properly. The formula has $\sin(C)$ , so you know that your given angle needs to be $C$ , which means the side opposite should be labelled as $c$ .

Now, use the formula:

$Area=\frac{1}{2}ab\sin(C)$

Substitute in known values:

$Area = \frac{1}{2}(2)(4)\sin(24)$

$Area =4\times \sin(24)=1.62694....$

$\underline{Area\,=1.63cm^2 \ (2 \ d.p.)}$

Learn with Basics

Length:

Unit 1

Trigonometric ratios: SOH CAH TOA

Unit 2

Finding missing lengths in a triangle

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Unit 3