Register Log in
Evulpo Logo

Benefit From a Yearly Subscription Now!

Save 44%

£11.99 / Month

£6.67 / Month

Chapter Overview

Maths

Exam board

Pearson Edexcel

Number

Algebra

Graphs

Ratio proportion and rates of change

Shapes and area

Angles and geometry

Trigonometry

Probability

Statistics

Maths

Order of operations: BODMAS

Your Lesson Progress
 
 
0%

Summary

Download

Order of operations: BODMAS

​​In a nutshell

BODMAS is used in multi-step calculations and when questions have a few different operations. BODMAS is an acronym for the order of operations, with the priority order of each operation. 


BODMAS = Bracket, Other, Division, Multiplication, Addition, Subtraction


Priority 
BODMAS
Symbol
1
Brackets
​()()​​​
2
Other
​x, xn\sqrt{x},\, x^n​​
3
Division
​÷\div​​
Multiplication
​×\times​​​
4
Addition 
​++​​
Subtraction
​−-​​


Note: When there is both multiplication and division, or addition and subtraction in the question, you work from left to right.


Procedure

1.
Calculate the value inside the brackets.
2.
Calculate the value of any terms raised to a certain power.
3.
Calculate the value of any terms being multiplied and/or divided.
4.
Calculate the value of any additions and/or subtractions.

​​

Example 1

Calculate the positive solution to (26−18)×9(26 - 18) \times \sqrt9


First calculate what is inside the brackets: 

(26−18)=8(26 - 18) = 8 ​​


Secondly calculate the other operation, such as square root of 99:

9=3\sqrt 9 = 3


Lastly multiply the results together: 

8×3=248 \times 3 = 24​​


Therefore, the answer is (26−18)×9=24‾(26 - 18 ) \times \sqrt9 = \underline{24}​


Note: ​The reason the question specifies 'positive solution' is because, strictly speaking, 9=±3\sqrt{9}=\pm3.  −3-3 is also a solution to 9\sqrt{9} which would yield a 'negative' solution to the question also.


Example 2

Evaluate the positive solution to (8−4)×1523+7\dfrac{\sqrt{(8-4)}\times15}{2^3+7}


First calculate what is inside the brackets:

8−4=48-4 = 4


Calculate the other operations such as square root then the indices:

4=223=8\sqrt4 = 2\\ 2^3= 8

​

Now the fraction becomes:

2×158+7\dfrac{2 \times 15}{8 +7}


Now you may want to carry out this fraction first as it is division but in this case treat each the numerator and denominator like they have separate brackets:

(2×15)(8+7)=3015\dfrac{(2 \times 15)}{(8+7)} = \dfrac{30}{ 15} ​​


Calculate the final division: 

3015=2\dfrac{30}{15}= 2


Therefore the positive solution to (8−4)×1523+7=2‾\dfrac{\sqrt{(8-4)}\times15}{2^3+7} = \underline{2} 



Frequently Asked Questions (FAQ)