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Area and perimeter: Triangles and quadrilaterals

Area and perimeter: Triangles and quadrilaterals

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Summary

Area and perimeter: Triangles and quadrilaterals

​​In a nutshell

The perimeter and area are unique properties of every shape. The perimeter and area of triangles and quadrilaterals can be calculated using different formulae. 



Perimeter 

The perimeter is the distance around the outside of a 2d2d shape. This is the sum of all the lengths of the outer sides of a given shape.


Example 1

What is the perimeter of the shape below?


Maths; Measures; KS3 Year 7; Area and perimeter: Triangles and quadrilaterals

 

Calculate the sum of all the outer sides.

4+3+5+2=14m4+3+5+2 = 14m​​


Therefore, the perimeter is 14m\underline{14m}.​​


Note: Ensure all the units are the same for each length before adding them together. 



Area

The area is the size of a shape's surface. There are different formulae to calculate the areas of different shapes. You will need to learn the following formulae.


SHAPE

FORMULA

ILLUSTRATION

Triangle

Area=12×base×perpendicular height\text{Area}=\frac{1}{2}\times\text{base}\times\text{perpendicular\,height}​​


A=12bhA=\dfrac{1}{2}bh​​

Maths; Measures; KS3 Year 7; Area and perimeter: Triangles and quadrilaterals
bb​​

Rectangle

Area=length×width\text{Area}=\text{length}\times\text{width}​​


A=lwA=lw​​

Maths; Measures; KS3 Year 7; Area and perimeter: Triangles and quadrilaterals

Parallelogram

Area=base×perpendicular height\text{Area}=\text{base}\times\text{perpendicular\,height}​​


A=bhA=bh​​

Maths; Measures; KS3 Year 7; Area and perimeter: Triangles and quadrilaterals

Trapezium

Area=12×(a+b)×height\text{Area}=\dfrac{1}{2}\times(a+b)\times\text{height},


A=12(a+b)×hA=\dfrac{1}{2}(a+b)\times h​​

Maths; Measures; KS3 Year 7; Area and perimeter: Triangles and quadrilaterals



Example 2

What is the area of the triangle below?


Maths; Measures; KS3 Year 7; Area and perimeter: Triangles and quadrilaterals


Identify the formula for the area of a triangle.

Area=12×base×perpendicular height{Area}=\dfrac{1}{2}\times{base}\times{perpendicular\,height}​​


Identify the relevant values. 

Base=4cmPerpendicular height=4cm\begin{aligned} &{Base} &= 4cm \\&{Perpendicular \ height} &= 4cm \end{aligned}​​


Place the values into the formula.

 Area=12×4×4{Area}=\dfrac{1}{2}\times 4 \times 4

​​

Area=8cm2\underline{{Area}=8 cm^2}​​


Note: Area is measured in square units.


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Exercises

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FAQs - Frequently Asked Questions

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